Unit of the eigenvalues of the PCA

Issue #660 resolved
Former user created an issue

Hi,

I am new to the topic of PCA and now I have a question regarding the eigenvalues. If I perform a PCA on a trajectory, which unit do the eigenvectors have? Angstrom? Or nanometers?

Thanks in advance for helping me!

Comments (2)

  1. Xinqiu Yao

    Eigenvectors are normalized and so there is no unit. For eigenvalues, it is 'angstrom square', because they represent the variance along each PC.

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