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sthen  committed 05b0691

Make it clear that the default implicit 'pass' rule does not create state,
make sense to deraadt@, ok/wording tweak from mikeb.

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File share/man/man5/pf.conf.5

-.\"	$OpenBSD: pf.conf.5,v 1.525 2013/01/16 02:43:24 henning Exp $
+.\"	$OpenBSD: pf.conf.5,v 1.526 2013/02/19 23:01:15 sthen Exp $
 .\"
 .\" Copyright (c) 2002, Daniel Hartmeier
 .\" All rights reserved.
 .\" ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE
 .\" POSSIBILITY OF SUCH DAMAGE.
 .\"
-.Dd $Mdocdate: January 16 2013 $
+.Dd $Mdocdate: February 19 2013 $
 .Dt PF.CONF 5
 .Os
 .Sh NAME
 .Ar pass ,
 the last matching rule decides what action is taken;
 if no rule matches the packet, the default action is to pass
-the packet.
+the packet without creating a state.
 For
 .Ar match ,
 rules are evaluated every time they match;