Setting up the location manually

[mschanz]

Hi,

kannst du mir sagen, wie ich manuell die Location setze? Wenn ich ojoc.py starte wird bei mir eine komplett falsche Stadt angezeigt?! Frage wäre also was da im Hintergrund passiert und gibt es eine Möglichkeit, dass ich manuell poste wo ich will. Bspw. ich spote in Aachen obwohl ich in Dresden bin.

[Christian Fibich]

Answering in English because it might be useful to others:

If no location is provides, OJOC/Connection.py uses an IP-to-location service to derive the location from the IP you get from your ISP. This may be off sometimes.

You can provide a location on a city-level granularity executing ojoc.py from the command line using the -c command-line option:

./ojoc.py -c CITY,CC where CC is the country code (e.g, "DE", "AT", "SE" or whatever)

e.g.,

./ojoc.py -c Vienna,AT sets your location to Vienna.

The "Arrow" button in the title bar should also open a map where you can change your location.

[mschanz]

Thanks for your fast response!

So, if I just want to use your implementation of the "connection", I could do something like

import OJOC.Connection

def post(msg):
  c = OJOC.Connection.Connection(location=Vienna, citycc=AT)
  c.new_post(msg)

and it should work fine? Because that isn't working at the moment. It looks like its posted, but I cannot see anything in my app.

[Christian Fibich]

OK, it should be

Connection.Connection(citycc="Vienna,AT")

or

Connection.Connection(location={'city':'Vienna', 'name':'Vienna', 'country':'AT', 'loc_accuracy':100, 'loc_coordinates': {'lat':48.1, 'lng':16.2}})

[mschanz]

Works fine, thx.

[mschanz]

Solved! :)

[Christian Fibich]

EDIT: Too late

To pass your own UID instead of querying the keyring pass it in the uid optional parameter of the constructor:

Connection.Connection(citycc="Vienna,AT", uid="deadbeef...")

[Christian Fibich]

Documentation bug at most