u() function does not support unicode character escapes

Matt Chaput avatarMatt Chaput created an issue

If I do:

six.u("\u1234")

in Python 2.x I should get:

u'\u1234'

but instead I get:

u'\\uABCD'

Unfortunately the only way I can think of to fix this is to loop through the unicode string with a regular expression and rebuild the string to replace \\u([0-9a-fA-F]{4}) with unichr(int(match.group(1), 16)) if you see what I mean.

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