CRF diffs relatively bit rate diffs formula

Please publicize in your docs a formula how to expect a new bitrate2 (at least at first approximation) if we know CRF1 and its result bitrate1.

a formula is close to be the same to dB of electrical amperage or voltage scale: dB diff (of voltage or amperage) = 10 lg v1 / v2 10 times of (ratio log with base of 10)

bitrate1 / bitrate2 = 2 if CRF2 - CRF1 = 3 dB

Example: we have CRF 23.7 and result bit rate is 3200kbps. how to make result bit rate about 2600kbps? 10 times of lg ( 3200 / 2600 ) = aprox. 0.9. So CRF catch for 2600kbps will be about 23.7 + 0.9 = 24.6 (of course it works for exactly the same footage/clip). And it works in practice.

Please add it or more accurate formula to your docs.

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