Issue #55 resolved

PyQuery constructor from filename fails

Jeff Lowdermilk
created an issue

Not sure why this hasn't been discovered yet, except perhaps no one uses the 'filename' kwarg. Fix is simple. In pyquery/

155 156 if kwargs: 157 # specific case to get the dom 158 if 'filename' in kwargs: 159 - html = open(kwargs['filename']) 159 + html = open(kwargs['filename']).read() 160 elif 'url' in kwargs:.

Just needs that and a test to exercise this path in the constructor.

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