Include a href in results

[Marckr P]

Hello,

Firstly, thanks for the efforts of making this program and making it available, it's a great solution for Django! Secondly, I am not sure if this is the correct place for an inquiry: I could not find a mailing list or support forum...

I have a datatable which has clickable links in the table results. Before using datatables with server side processing, my template would create the link from the object's slug. How would I go about doing the same when using a table created by django-datatables-view?

Best, Marcks

[Marckr P]

I made a custom render_column definition in the class defined in my views.py. It is the below code. Note that my model name and url name are the same, except that the model was typed with a upper case first letter. Adjust the url reversal for your own typical case.

    def render_column(self, row, column):
        if hasattr(row, 'get_%s_display' % column):
            text = getattr(row, 'get_%s_display' % column)()
        else:
            try:
                text = getattr(row, column)
            except AttributeError:
                obj = row
                for part in column.split('.'):
                    if obj is None:
                        break
                    obj = getattr(obj, part)
                text = obj
        if text is None:
            text = self.none_string

        if text and row.slug:
            return '<a href="%s">%s</a>' % (reverse(str.lower(self.model.__name__), args=(row.slug,)), text)
        else:
            return text

[Maciej Wisniowski]

It can be done with renderer column or by defining own prepare_results function. Have a look at Readme and example in Another example of views.py customisation section

[Marckr P]

Thanks, I redid it with a prepare_results function. It's much cleaner now and easier to use. Thanks for your help!