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rbeezer committed 67b65b1

Solution LDS.T55, B should be C at very end (Chris Spalding)

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 Typo: Example LDRN, use Theorem LIVRN as justification (Anna Dovzhik)
 Typo: Sage RLD, "nest" to "next" (Gavin Tranter)
 Typo: Theorem OSLI, "nozero" to "nonzero"  (Anna Dovzhik)
+Typo: Solution LDS.T55, B should be C at very end (Chris Spalding)
                                                 
                                                     
 v3.10 2013/08/20

File src/section-LDS.xml

 \colvector{3 \\ 0 \\ 6}
 }
 </equation>
-and then $\spn{S}=\spn{T}$.  $T$ is also a linearly independent set, which we can show directly.  Make a matrix $C$ whose columns are the vectors in $S$.  Row-reduce $B$ and you will obtain the identity matrix $I_3$.  By <acroref type="theorem" acro="LIVRN" />, the set $S$ is linearly independent.
+and then $\spn{S}=\spn{T}$.  $T$ is also a linearly independent set, which we can show directly.  Make a matrix $C$ whose columns are the vectors in $S$.  Row-reduce $C$ and you will obtain the identity matrix $I_3$.  By <acroref type="theorem" acro="LIVRN" />, the set $S$ is linearly independent.
 </solution>
 </exercise>