Commits

committed 67b65b1

Solution LDS.T55, B should be C at very end (Chris Spalding)

• Participants
• Parent commits 87f9ebc

File changes.txt

` Typo: Example LDRN, use Theorem LIVRN as justification (Anna Dovzhik)`
` Typo: Sage RLD, "nest" to "next" (Gavin Tranter)`
` Typo: Theorem OSLI, "nozero" to "nonzero"  (Anna Dovzhik)`
`+Typo: Solution LDS.T55, B should be C at very end (Chris Spalding)`
`                                                 `
`                                                     `
` v3.10 2013/08/20`

File src/section-LDS.xml

` \colvector{3 \\ 0 \\ 6}`
` }`
` </equation>`
`-and then \$\spn{S}=\spn{T}\$.  \$T\$ is also a linearly independent set, which we can show directly.  Make a matrix \$C\$ whose columns are the vectors in \$S\$.  Row-reduce \$B\$ and you will obtain the identity matrix \$I_3\$.  By <acroref type="theorem" acro="LIVRN" />, the set \$S\$ is linearly independent.`
`+and then \$\spn{S}=\spn{T}\$.  \$T\$ is also a linearly independent set, which we can show directly.  Make a matrix \$C\$ whose columns are the vectors in \$S\$.  Row-reduce \$C\$ and you will obtain the identity matrix \$I_3\$.  By <acroref type="theorem" acro="LIVRN" />, the set \$S\$ is linearly independent.`
` </solution>`
` </exercise>`
` `