Deserializing problem

[Marco Demartino]

Hi,

I am deserializing a class, saving it to file and right after it I am loading and serializing it, but it outputs an error and I can't understand why. The code is available on GitHub https://github.com/SuperMarcomen/SuperLib.
Here is the error: https://pastebin.com/3s3RRbpZ

Even tough there is an error during the serialization, the deserialization works fine, but I would like to change the output a bit, but I can't understand how to do it.

!!it.marcodemartino.superlib.Config
location: {serializedLocation: 'world:0.0:0.0:0.0:0.0:0.0'}
pirla: test

As you can see, SnakeYaml saves the instance of SerializableLocation with the name "location" and then it saves its field "serializedLocation", but I would like to have just a string called "location" as output.

[Andrey Somov]

This is confusing.

1. you say that that serialisation failed but I do not see a failure
2. you say deserialization works fine, but I see the exception during deserialization
3. what you want to get in completely unclear
4. can you please provide your exact expectation ?
5. stackoverfow or mailing list is a better place to ask a question (this is an issue tracker, but there is no issue)

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[Marco Demartino]

Thank you so much for your reply.

I’m sorry if my request was confusing, I’ve confused “serialization” with “deserialization”.

I didn’t realize there was a better place to ask my question, therefore I will move it there right now.

[Marco Demartino]

Moved to mailing list