euler / haskell / 6.hs

-- The sum of the squares of the first ten natural numbers is,
-- 
-- 12 + 22 + ... + 102 = 385
-- The square of the sum of the first ten natural numbers is,
-- 
-- (1 + 2 + ... + 10)2 = 552 = 3025
-- Hence the difference between the sum of the squares of the first ten natural
-- numbers and the square of the sum is 3025  385 = 2640.
-- 
-- Find the difference between the sum of the squares of the first one hundred
-- natural numbers and the square of the sum.
-- 
-- 
-- Answer: 25164150

main = print $ (sum [1..100] * sum [1..100]) - sum [x*x | x <- [1..100]]
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