execute monit command in bash script

[david.fazeli]

hi. i want in my bash script myscript.sh execute monit script . example :

monit file is:

check process mariadb with pidfile /var/mysql/mysql.pid
if failed then exec "another_script.sh"

if we want this monit file, execute by one script then return result? for sample:

#!/bin/bash

check process mariadb with pidfile /var/mysql/mysql.pid
if failed then exec "another_script.sh"

[root@server]# ./script.sh ; echo $?

[Tildeslash]

Hello David,

you can use the "check program", which allows for return value (status) testing. The exec action then allows to execute another script on failure: https://mmonit.com/monit/documentation/monit.html#PROGRAM-STATUS-TEST