commit to default branch

Issue #5265 duplicate
Sviluppo
created an issue

hello, i'm in another branch and i want to commit to default branch, but this happened, so as the window says i'm here to post it, hope you can help me

thanks

    #!python
    ** Mercurial version (4.7.1).  TortoiseHg version (4.7.1)
    ** Command: 
    ** CWD: C:\WINDOWS\System32
    ** Encoding: cp1252
    ** Extensions loaded: tortoisehg.util.configitems
    ** Python version: 2.7.13 (v2.7.13:a06454b1afa1, Dec 17 2016, 20:53:40) [MSC v.1500 64 bit (AMD64)]
    ** Windows version: sys.getwindowsversion(major=6, minor=2, build=9200, platform=2, service_pack='')
    ** Processor architecture: x64
    ** Qt-5.9.2 PyQt-5.9.1 QScintilla-2.10.2.dev1711012104
    Traceback (most recent call last):
      File "tortoisehg\hgqt\commit.pyo", line 600, in mqPerformAction
      File "tortoisehg\hgqt\commit.pyo", line 973, in commit
      File "tortoisehg\hgqt\commit.pyo", line 572, in getBranchCommandLine
      File "tortoisehg\hgqt\thgrepo.pyo", line 772, in __getitem__
      File "mercurial\localrepo.pyo", line 856, in __getitem__
      File "mercurial\context.pyo", line 439, in __init__
    ProgrammingError: unsupported changeid 'default' of type <type 'str'>